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11 May, 10:42

When 25.4 g NaNO3 is dissolved in water to make 1250 mL of solution, what is the molarity of the solution?

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  1. 11 May, 10:55
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    Molarity = 0.24 mol/L

    Explanation:

    Given dа ta:

    Mass of NaNO3 = 25.4 g

    Volume of solution = 1250 mL

    Molarity = ?

    Solution:

    Molarity of solution is equal to the number of moles of solute divided by volume of solution in litter.

    Formula:

    Molarity = number of moles / volume in L

    First of all we will convert the volume in litter.

    1 L = 1000 mL

    1250 / 1000 = 1.25 L

    Now we calculate the moles of NaNO3 in present in 25.4 g.

    Number of moles = mass / molar mass

    Molar mass of NaNO3 = (23 + 14 + 16*3) = 85 g/mol

    Number of moles = 25.4 g / 85 g/mol

    Number of moles = 0.299 mol

    Now we will calculate the molarity of solution

    Molarity = number of moles / volume in L

    Molarity = 0.299 mol / 1.25 L

    Molarity = 0.24 mol/L
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