Which of the following systems (i. e., pair of metals) would you expect to exhibit complete solid solubility? Cr-V Mg-Zn Al-Zr

The system that will exhibit complete solid solubility is Cr-V

Explanation:

The following factors must be examined to check which of the systems that will exhibit complete solubility

1. Crystal Structure (Same or Different)

2. The difference of their atomic radius has to be less than ±15% and

3. The difference in electronegativity

Having highlighted these factors, we'll check for each of the pair of metals

1.

Cr - V

Chromium and Vanadium

Cr

Electronegativity = 1.6

Atomic Radius = 0.125

Vanadium.

Electronegativity = 1.6

Atomic Radius = 0.132

Difference in atomic radius = (0.125 - 0.132) / 0.125

Difference = - 0.007/0.125

Difference = - 0.056

Difference = - 5.6%

a. They have the same crystal structure

b. They have the same electronegativity

c. Difference in atomic radius is less than ±15%

2.

Mg - Zn

Magnesium and Zinc

Magnesium

Electronegativity = 1.2

Atomic Radius = 0.16

Zinc

Electronegativity = 1.6

Atomic Radius = 0.133

Difference in atomic radius = (0.16 - 0.133) / 0.16

Difference = 0.027/0.16

Difference = 0.16875

Difference = 16.875%

They have the different electronegativity

The Difference in atomic radius is greater than ±15%

3.

Al - Zr

Aluminum and Zirconium

Aluminum

Electronegativity = 1.5

Atomic Radius = 0.143

Zirconium

Electronegativity = 1.4

Atomic Radius = 0.148

Difference in atomic radius = (0.143 - 0.148) / 0.143

Difference = - 0.005/0.143

Difference = - 0.034965

Difference = - 3.4965%

a. They have the same crystal structure

b. They have the different electronegativity

c. Difference in atomic radius is less than ±15%