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31 January, 18:03

How many aluminum atoms are in 2.58 grams of aluminum

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  1. 31 January, 20:54
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    5.75x10^22 atoms

    Explanation:

    From a clear understanding of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms. This implies that 1mole of Al also contains 6.02x10^23 atoms.

    1mole of Al = 27g

    If 27g of Al contains 6.02x10^23 atoms, then 2.58g of Al will contain = (2.58 x 6.02x10^23) / 27 = 5.75x10^22 atoms
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