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4 November, 01:09

Calculate the theoretical oxygen demand (mg/L). of a solution containing 450mg of glucose (C6H12O6). in 2 L of distilled water.

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  1. 4 November, 04:51
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    ThOD = 239.792 mg/L

    Explanation:

    Theorical Oxigen demand (ThOD):

    is the theoretical amount of oxygen

    required to oxidize the organic fraction of a

    waste up to carbon dioxide and water.

    ⇒ C sln = 450 mg C6H12O6 / 2 L H2O = 225 mg/L sln

    ∴ mm C6H12O6 = 180.156 g/mol

    balanced reaction:

    C6H12O6 + 6O2 → 6CO2 + 6H2O

    ∴ mol C6H12O6 = 1 mol

    ⇒ mass C6H12O6 = (180.156 g/mol) (1 mol) = 180.156 g

    ∴ the value of ThOD is determined when 180.156 g C6H12O6 consume mass O2 = 6 (32) = 192 g Oxygen; then in a solution of 225 mg/L, you have:

    ⇒ ThOD = (192/180.156) * 225 mg/L

    ⇒ ThOD = 239.792 mg/L
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