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24 February, 02:32

A solution of hydrocloric acid has a molarity of 2.25 M HCl. If a reaction requires 5.80 g of HCI, what

volume of a solution should be used? Assume a molecular mass of 36.45 g for the HCI.

Calculate the number of moles of solute required:

g)

(36.45 g/mol) =

mol HCI

DONE

+3
Answers (1)
  1. 24 February, 06:30
    0
    0.071L

    Explanation:

    From the question given, we obtained the following dа ta:

    Molarity of HCl = 2.25 M

    Mass of HCl = 5.80g

    Molar Mass of HCl = 36.45g/mol

    Number of mole of HCl = ?

    Number of mole = Mass / Molar Mass

    Number of mole of HCl = 5.8/36.45 = 0.159mole

    Now, we can obtain the volume required as follows:

    Molarity = mole / Volume

    Volume = mole / Molarity

    Volume = 0.159mole / 2.25

    Volume = 0.071L
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