Ask Question
10 January, 12:00

Show Work for any of these

1. What is the molarity of a solution made with 25.2 g CaO in a total of 2 L of solution? Show your work, using dimensional analysis, being sure to use units throughout.

2. Calculate the molarity of the solution formed when 0.72 moles of CaBr2 is dissolved in 1.50 L water. Show your work

3. Find the molar mass of magnesium phosphate tribasic, which has a formula of Mg3 (PO4) 2

+2
Answers (1)
  1. 10 January, 12:57
    0
    1. 0.224 M is the molarity of the solution made with 25.2 grams CaO in 2 litres of solution.

    2. 0.48 M is the molarity of the solution formed when 0.72 moles of CaBr2 is dissolved in 1.50 L water.

    3. 262.84 gm/mole is the molar mass of Mg3 (PO4) 2.

    Explanation:

    1. Data given:

    weight of the mass of CaO = 25.2 grams

    Atomic weight of one mole of CaO = 56.07 gram/mole

    number of moles = mass:atomic mass of one mole of the substance

    = 25.2 : 56.07

    = 0.449 moles of CaO is used to make a solution of 2 Litres

    formula for molarity:

    molarity = number of moles : volume in litres

    = 0.449 : 2

    = 0.224 M

    2. Data given:

    number of moles of CaBr2 = 0.72 moles

    volume of the water used = 1.50 L

    Formula of molarity:

    molarity = number of moles : volume in litres

    molarity = 0.72 : 1.5

    = 0.48 M

    3. Molar mass of a compound is calculated by adding the number of moles of elements taking part in the formation of the compound.

    Mg = 24.30 gm/mole

    P = 30.97 gm/mole

    O = 16 gm/mole

    3 moles of Mg (24.3 x 3) + 2 moles of P (2 x 30.97) + 8 moles of O (8 x 16)

    = 262.84 gm/mole is the atomic weight of Mg3 (PO4) 2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Show Work for any of these 1. What is the molarity of a solution made with 25.2 g CaO in a total of 2 L of solution? Show your work, using ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers