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21 April, 15:03

Rubbing alcohol contains 585 g isopropanol (C3H7OH) in 1000 mL of solution (aqueous solution). Calculate the molarity.

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  1. 21 April, 15:53
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    The molarity of the solution is 9.73 M

    Explanation:

    Step 1: Data given

    Mass of isopropanol = 585 grams

    Molar mass of isopropanol = 60.1 g/mol

    Volume = 1000 mL = 1 L

    Step 2: Calculate moles of isopropanol

    Moles isopropanol = mass isopropanol / molar mass isopropanol

    Moles isopropanol = 585 grams / 60.1 g/mol

    Moles isopropanol = 9.73 moles

    Step 3: Calculate molarity of the solution

    Molarity = moles / volume

    Molarity = 9.73 moles / 1L

    Molarity = 9.73 M

    The molarity of the solution is 9.73 M
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