What is the amount of oxygen found in 13.15 grams of sodium acetate.

5.3 g

Explanation:

Data Given:

Sodium acetate CH₃COONa = 13.5 g

Amount of oxygen = ?

Solution:

Molecular weight calculation:

CH₃COONa = 12 + 1 x 3 + 12 + 16 x 2 + 23

CH₃COONa = 82 g/mol

Mass contributed by oxygen = 32 g

calculate the mole percent composition of oxygen in sodium acetate

Since the percentage of compound is 100

So,

Percent of Oxygen = 32 / 82 x 100

Percent of Oxygen = 39 %

it means that for ever gram of sodium acetate there is 0.39 g of oxygen is present.

So, for 13.5 g the mass of Oxygen well be

mass of Oxygen = 0.39 x 13.5

mass of Oxygen = 5.3 g