If 600.0 ml of air is heated from 293 k to 333 k what volume will it occupy

V1 = 600.0 mL

T1 = 293 K

V2 unknown

T2 = 333K

Charles law V1*T2=V2*T1

where V1 and T1 are the initial volume and temperature. V2 and T2 are the final temperature and volume.

V2 = (V1*T2) / T1 = (600.0*333) / 293 = 682 mL (with significant figures) (681.911 mL before signifcant figures.)