Ask Question
4 February, 19:56

How many grams of magnesium metal will react completely with 6.3 liters of 4.5 M HCl? Show all of the work needed to solve this problem.

Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)

+3
Answers (1)
  1. 4 February, 21:56
    0
    Mg (s) + 2 HCl (aq) - > MgCl2 (aq) + H2 (g)

    1) Number of mols of HCl, n

    n = 6.3 L * 4.5 mol/L = 28.35 mol

    2) ratio: 2 mol HCl / 1 mol Mg = 28.35 mol HCl / x mol Mg

    x = 28.35 mol HCL * 1 mol Mg / 2 mol HCL = 14.175 mol Mg

    3) Convert mol to mass using atomic mass of Mg

    14.175 mol Mg * 24.3 g Mg / mol Mg = 344. 45 g

    Answer: 344.45 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of magnesium metal will react completely with 6.3 liters of 4.5 M HCl? Show all of the work needed to solve this problem. Mg ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers