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3 February, 05:37

The terms Q and K describe mass action for reactions at non-equilibrium and equilibrium conditions, respectively. For a forward reaction to being favored in a living cell, which of the following statements must be true?

a. The value of K must be less than that of Q.

b. The value of Q must be less than that of K.

c. No conclusion can be drawn about Q and K for a favorable process.

d. None of the listed statements are true; cells are at equilibrium.

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  1. 3 February, 07:49
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    Q should be less than K for the forward reaction to be favoured (option C)

    Explanation:

    Since the standard gibbs free energy is

    ΔG = ΔG⁰ + RT*ln Q

    where Q = [P1]ᵃ ... / ([R1]ᵇ ...), representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

    when the system reaches equilibrium ΔG=0 and Q=Keq

    0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

    therefore the first equation also can be expressed as

    ΔG = RT*ln (Q/Keq)

    since R and T are always positive:

    ΔG<0 if Q0 if Q>Keq (thus the reverse reaction is favoured)

    therefore Q should be less than K for the forward reaction to be favoured
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