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22 October, 16:26

What is the volume of a 0.0355mol/L calcium hydroxide solution required to react completely with 50.0mL of 0.250mol/L aluminum sulfate solution

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  1. 22 October, 18:58
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    V₁ = 0.35 L

    Explanation:

    Given dа ta:

    Molarity of calcium hydroxide = 0.0355 M

    Volume of aluminium sulfate = 50.0 mL (50/1000 = 0.05 L)

    Molarity of aluminium sulfate = 0.250 M

    Volume of calcium hydroxide = ?

    Solution:

    M₁V₁ = M₂V₂

    V₁ = M₂V₂ / M₁

    V₁ = 0.250 M. 0.05 L / 0.0355 M

    V₁ = 0.0125 M. L / 0.0355 M

    V₁ = 0.35 L
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