Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What was the final temperature of the water?

Question

Chemistry

Yusuf Kim

3 April, 04:05

Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What was the final temperature of the water?

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Answers (1)

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Angel Estes · Answer 1

T final = 80°C

Explanation:

Q = mCpΔT

∴ Q = 18000 cal

∴ m H2O = 300 g

∴ Cp H2O (15°C) = 0.99795 cal/g. K ≅ 1 cal/g. K

∴ T1 = 20°C = 293 K

∴ T2 = ?

⇒ 18000 cal = (300 g) (1 cal/g. K) (T2 - 293 K)

⇒ (18000 cal) / (300 cal/K) = T2 - 293 K

⇒ T2 = 293 K + 60 K

⇒ T2 = 353 K (80°C)