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3 April, 04:05

Cindy made tea. She started with 300 grams of water at 20 degrees Celsius. She transferred 18,000 calories to the water. What was the final temperature of the water?

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  1. 3 April, 04:43
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    T final = 80°C

    Explanation:

    Q = mCpΔT

    ∴ Q = 18000 cal

    ∴ m H2O = 300 g

    ∴ Cp H2O (15°C) = 0.99795 cal/g. K ≅ 1 cal/g. K

    ∴ T1 = 20°C = 293 K

    ∴ T2 = ?

    ⇒ 18000 cal = (300 g) (1 cal/g. K) (T2 - 293 K)

    ⇒ (18000 cal) / (300 cal/K) = T2 - 293 K

    ⇒ T2 = 293 K + 60 K

    ⇒ T2 = 353 K (80°C)
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