How many moles of nacl are present in 600 ml of a 1.55 m nacl solutions

The answer is 2.583 moles

Explanation:

molarity is defined as the number of moles divided by the volume of the solution, as follows:

M = nmoles/Volume

Clearing the nmoles:

600 mL = 0.6 L

nmoles = MxVolume = 1.55 mol/L x 0.6 L = 2.583 moles