A 45.0L gas cylinder contains 988 He at 23 degrees C what is the pressure inside the cylinder

P = 133.4 atm

Explanation:

Given dа ta:

Mass of helium = 988 g

Volume = 45.0 L

Temperature = 23°C (23+273 = 296 K)

Pressure of cylinder = ?

Solution:

Number of moles of helium:

Number of moles = mass / molar mass

Number of moles = 988 g / 4 g/mol

Number of moles = 247 mol

Pressure:

PV = nRT

P = nRT/V

P = 247 mol * 0.0821. atm. L/mol. K * 296 K / 45 L

P = 6002.5 / 45 L

P = 133.4 atm