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19 May, 03:54

To what volume should you dilute 134 mL of an 8.00 M CuCl2 solution so that 48.0 mL of the diluted solution contains 5.89 g CuCl2? Express your answer in milliliters.

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  1. 19 May, 06:20
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    Number of moles of CuCl2 initially present = volume * molar concentration

    = 0.134 * 8

    = 1.072 mol.

    Molar mass of CuCl2 = 63.5 + (2*35.5)

    = 134.5 g/mol

    Mass of CuCl2 = molar mass * number of moles

    = 134.5 * 1.072

    = 144.184 g

    Mass of CuCl2 in 48 ml = 5.89 g in 48 ml

    Volume = 5.89 * (48/144.184)

    = 1.96 ml.
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