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ChemistryChemistry
29 January, 07:15

Calculate the molarity of the solutions described below.

A. 10.0 g of sodium chloride is dissolved in 2.0 L of solution.

B. 52.5 g of sugar (C12H22O11) s dissolved in 1.0 L of solution.

C. 120 g of aluminum sulfate is dissolved in 10.0 L of solution.

D. 1.75 g of caffeine (C8H10N4O2) is dissolved in 0.100 L of solution.

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Answers (1)
  1. 29 January, 11:07
    0
    A. Na = 23 g/m Cl = 35.5 g/m NaCl = 58.5 g/m

    10g / 58.5 g/m =.17 mole

    .17 mole / 2.0 L = 0.086 m/L = 0.086 Molar

    B. 342 g/m 52.5/342 = 0.15 mole 0.15 mole/1.0 L = 0.15 Molar

    C. Al2 (SO4) 3= = 342 g/m 120/342 = 0.35 mole 0.35 m/10. L 0.035 Molar

    D caffeine = 194 g/m 1.75 / 194 = 0.009 mole 0.009/0.100 L 0.09 Molar
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Home » Chemistry » Calculate the molarity of the solutions described below. A. 10.0 g of sodium chloride is dissolved in 2.0 L of solution. B. 52.5 g of sugar (C12H22O11) s dissolved in 1.0 L of solution. C. 120 g of aluminum sulfate is dissolved in 10.0 L of solution.
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