Calculate the value of [N2]eq if [H2]eq = 2.0 M, [NH3]eq = 0.5 M, and Kc = 2. N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) 0.062 M62.5 M0.40 M0.016 M0.031 M

[ N₂ (g) ] = 0.016 M

Explanation:

N₂ (g) + 3 H₂ (g) ↔ 2 NH₃ (g)

The equilibrium constant for the above reaction, can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation.

Hence,

Kc = [ NH₃ (g) ]² / [ N₂ (g) ] [ H₂ (g) ]³

From the question,

[ NH₃ (g) ] = 0.5 M

[ N₂ (g) ] = ?

[ H₂ (g) ] = 2.0 M

Kc = 2

Now, putting it in the above equation,

Kc = [ NH₃ (g) ]² / [ N₂ (g) ] [ H₂ (g) ]³

2 = [ 0.5 M ]² / [ N₂ (g) ] [ 2.0 M ]³

[ N₂ (g) ] = 0.016 M.