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7 August, 06:36

Calculate the molarity of the two solutions.

a). The first solution contains 0.550 mol of NaOH in 2.50 L of solution.

b). The second solution contains 15.7 g of NaCl in 709 mL of solution.

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Answers (1)
  1. R
    7 August, 08:35
    0
    A = Molarity = 0.22 M

    B = Molarity = 0.36 M

    Explanation:

    Given dа ta:

    For first solution:

    number of moles = 0.550 mol

    Volume of solution = 2.50 L

    Molarity = ?

    Molarity:

    Formula:

    Molarity = number of moles of solute / volume of solution in L.

    Molarity = 0.550 mol / 2.50 L

    Molarity = 0.22 M

    For second solution:

    Mass of NaCl = 15.7 g

    Volume of solution = 709 mL or 709/1000 = 0.709 L

    Molarity = ?

    Solution:

    Number of moles = mass / molar mass

    Number of moles = 14.7 g / 58.44 g/mol

    Number of moles = 0.252 mol

    Molarity:

    Molarity = number of moles of solute / volume of solution in L.

    Molarity = 0.252 mol / 0.709 L

    Molarity = 0.36 M
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