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8 November, 23:44

Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were cooled from 90.0oC to 30.0oC.

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  1. 9 November, 00:11
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    V₂ = 2.91 L

    Explanation:

    Given dа ta:

    Initial volume = 3.50 L

    Initial temperature = 90.0°C (90+273 = 363 K)

    Final temperature = 30.0 °C (30 + 273 = 303 K)

    Final volume = ?

    Solution:

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    V₁/T₁ = V₂/T₂

    3.50 L / 363 K) = V₂ / 303 K)

    V₂ = 0.0096 L/K * 303 K

    V₂ = 2.91 L
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