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Chemistry
Boston
9 February, 10:12
4. 213.4 grams of NaNO3 contain how many moles?
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Adolfo
9 February, 12:38
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mass of NaNO3 = 213.4g
Molar mass = {23 + 14 + 3 (16) }
= 23 + 14 + 48
= 85g/mol
Amount = mass/molar mass
= 213.4/85
= 2.5moles of NaNO3
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