A sample of iron metal absorbs 4.56j of heat, upon which temperature of the sample increased from 29 degrees c to 36 degrees c. Which if the following is the mass of the sample? cs of iron is 0.46j/g degrees.

Mass = 1.42 g

Explanation:

Given dа ta:

Amount of heat absorbed = 4.56 j

Initial temperature = 29°C

Final temperature = 36°C

Mass of iron metal = ?

Specific heat capacity of iron = 0.46 j/g.°C

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 36°C - 29°C

ΔT = 7°C

Q = m. c. ΔT

m = Q / c. ΔT

m = 4.56 j / 0.46 j/g°C. 7°C

m = 4.56 j / 3.22 j/g

m = 1.42 g