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14 May, 23:57

1.10 atoms of aluminum reacts with 6 molecules of oxygen gas to produce aluminum oxide.

4 Al + 3 02-> 2 Al2O3

How many atoms or molecules of the excess reactant remain?

a. 2 atoms

b. 6 molecules

c. 10 atoms

d. 3 molecules

+3
Answers (1)
  1. 15 May, 01:58
    0
    Answer: Option A) 2 atoms

    Explanation:

    4Al + 302 - --> 2Al2O3

    4 moles of Al reacts with 3 molecules of O2

    So 1.10 moles of Al should reacts with Z molecules of O2 (Assume Z is unknown)

    i. e 4 moles of Al = 3 molecules of O2

    4 moles of Al = 6 atoms of O2 (since 1 molecule of oxygen has two atoms of oxygen)

    1.10 atoms of Al = Z atoms of O2

    To get the value of Z, cross multiply

    Z x 4 moles = 6 atoms x 1.10 moles

    4Z = 6.6

    Divide both sides by 4

    4Z/4 = 6.6/4

    Z = 1.65 atoms (approximately 2 atoms)

    Thus, 2 atoms of the excess reactant oxygen remains.
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