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21 February, 04:30

1. If 6 moles of KNO3 should be produced in a reaction, but only 4.78 mol KNO3 are produced, what is the % yield?

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  1. 21 February, 05:48
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    79.7%

    Explanation:

    Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.

    In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:

    4.78 mol / 6 mol * 100 = 79.7%
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