how many grams of CsXeF7 can be produced from the reaction of 15.2 grams of CsF and 260 grams of XeF6?

39.72 g

Explanation:

Given dа ta:

Mass of CsF = 15.2 g

Mass of XeF₆ = 260 g

Mass of Cs[XeF₇] = ?

Solution:

Chemical reaction:

CsF + XeF₆ → Cs[XeF₇]

Number of moles of CsF:

Number of moles = mass / molar mass

Number of moles = 15.2 g/151.9 g/mol

Number of moles = 0.1 mol

Number of moles of XeF₆:

Number of moles = mass / molar mass

Number of moles = 260 g/245.28 g/mol

Number of moles = 1.06 mol

Now we will compare the moles of Cs[XeF₇] with both reactants.

CsF : Cs[XeF₇]

1 : 1

0.1 : 0.1

XeF₆ : Cs[XeF₇]

1 : 1

1.06; 1.06

Number of moles of Cs[XeF₇] produce by CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].

Mass of Cs[XeF₇]:

Mass = number of moles * molar mass

Mass = 0.1 mol * 397.2 g/mol

Mass = 39.72 g