Concentrated hydrochloric acid has a molarity of 6.0 M. How many mL of HCI must be used to make 500.0 mL of 2.0 M Hydrochloric acid?

The answer to your question is: 167 ml

Explanation:

Data

HCl = 6 M

Volume 1 = ?

HCl 2 = 2 M

Volume 2 = 500 ml

Formula

C1 V1 = C2 V2

V1 = C2V2 / C1

Process

V1 = (2 x 500) / 6

V1 = 1000 / 6

V1 = 166.7 ml ≈ 167 ml