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20 April, 04:07

A 0.050 M solution of AlCl3 had an observed osmotic pressure of 3.85 atm at 20 ∘C. Calculate the van't Hoff factor i for AlCl3.

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  1. 20 April, 05:57
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    Van't Hoff factor, for this solution is 3.2

    Explanation:

    Osmotic pressure formula → π = M. R. T. i

    π = Pressure → 3.85 atm

    M = Molarity → 0.05mol/L

    R = Constant for the Ideal Gases → 0.082 L. atm / mol. K

    T = Absolute T° (K) → T°C + 273

    20°C + 273 = 293K

    Let's replace dа ta:

    3.85 atm = 0.05 mol/L. 0.082 L. atm/mol. K. 293K. i

    3.85 atm / 0.05. 0.082 atm. 293 = i

    3.20 = i

    If we assume complete ionization, i must be ≅ 4

    AlCl₃ → Al³⁺ + 3Cl⁻

    We have 1 mol of aluminum cation and 3 moles of chloride, 4 total moles.
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