Ask Question
15 August, 02:04

What is the mass of 1.63 moles and f ammonium phosphorus (NH4) 3PO4

+3
Answers (1)
  1. 15 August, 03:30
    0
    mass (NH4) 3PO4 = 243.011 g

    Explanation:

    mass (NH4) 3PO4 = ?

    ∴ moles (NH4) 3PO4 = 1.63 moles

    ∴ molecular weight (Mw) = 149.0867 g/mol

    mass = (mol) * (Mw)

    ⇒ mass (NH4) 3PO4 = (1.63 mol (NH4) 3PO4) * (149.0867 g/mol)

    ⇒ mass (NH4) 3PO4 = 243.011 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the mass of 1.63 moles and f ammonium phosphorus (NH4) 3PO4 ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers