What is the mass of 1.63 moles and f ammonium phosphorus (NH4) 3PO4

Question

Chemistry

Juliana Harris

15 August, 02:04

What is the mass of 1.63 moles and f ammonium phosphorus (NH4) 3PO4

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Answers (1)

Know the Answer?

Helen Buckley · Answer 1

mass (NH4) 3PO4 = 243.011 g

Explanation:

mass (NH4) 3PO4 = ?

∴ moles (NH4) 3PO4 = 1.63 moles

∴ molecular weight (Mw) = 149.0867 g/mol

mass = (mol) * (Mw)

⇒ mass (NH4) 3PO4 = (1.63 mol (NH4) 3PO4) * (149.0867 g/mol)

⇒ mass (NH4) 3PO4 = 243.011 g