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20 September, 22:05

In a five-fold serial dilution of a 20 ug/mL solution, all tube dilutions are 1/5. What is the substance concentration in the third tube of this series?

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  1. 21 September, 00:07
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    In the third tube, the concentration is 0.16 ug/mL

    Explanation:

    In the first step, the solution is diluted by 5. Then, the concentration will be

    20 ug/mL / 5 = 4 ug/mL

    Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:

    4 ug / ml / 5 = 0.8 ug/mL

    This solution is then diluted again by 5 and the concentration in the third tube will be then:

    0.8 ug/mL / 5 = 0.16 ug/mL

    Another way to calculate this is to divide the original concentration by the dilution factor (5 in this case) elevated to the number of dilutions. In this case:

    Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL
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