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7 January, 08:46

A stock solution of Blue #1 has a concentration of 5.736 M. 3 mL of this solution is diluted with 8 mL water. What is the concentration of the resulting solution? Provide your response to 3 significant figures.

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  1. 7 January, 10:12
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    1.56 M

    Explanation:

    This is a dilution process and so a dilution formula is suitably used as follows C1V1 = C2V2 where

    C1 = concentration of the stock solution

    V1 = volume of the stock solution

    C2 = concentration of the resulting (dilute) solution and

    V2 = the volume of the resulting (dilute) solution

    C1V1 = C2V2 (Making C2 subject of the formula)

    C2 = C1V1/V2

    Given: C1 = 5.736 M; V1 = 3 Ml; V2 = (3+8) 11 Ml

    C2 = 5.736 x 3 / 11

    C2 = 1.56 M
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