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21 July, 07:29

A solution is prepared by dissolving 2.61 g ethanol (C2H5OH) in 16.2 g water. What is the molality (mol/kg) of C2H5OH in the solution?

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  1. 21 July, 10:06
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    3.50 molal

    Explanation:

    Molality → Moles of solute / kg of solvent.

    Let's convert the solvent's mass from g to kg

    16.2 g. 1kg / 1000 g = 0.0162 kg

    Let's determine the moles from the solute

    2.61 g. 1 mol / 46 g = 0.0567 moles

    Molality → 0.0567 mol / 0.0162 kg = 3.50 m
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