Ask Question
18 September, 08:36

Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 5 percent sulfuric acid, approximately how many liters of the 2 percent solution will be required?

+1
Answers (1)
  1. 18 September, 11:04
    0
    42 liters

    Explanation:

    Let the volume of 2% sulfuric acid required be X while that of 12% sulfuric acid required be Y.

    According to the concentration: 0.02X + 0.12Y = 0.05 (X + Y) ... equation 1

    According to the volume: X + Y = 60 ... equation 2

    Substitute equation 2 into equation 1.

    0.02X + 0.12 (Y) = 0.05 (60)

    2X + 12Y = 300

    X + 6Y = 150 ... equation 3

    From equation 2, Y = 60 - X ... equation 4

    Substitute equation 4 into equation 3.

    X + 6 (60-X) = 150

    X + 360 - 6X = 150

    -5X = - 210

    X = 42

    Hence, the volume of 2% sulfuric acid required is 42 liters.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers