3. What is the mass of HI used to create 2.50L of a 0.48 M solution of hydroiodic acid?

Mass = 153.48 g

Explanation:

Given dа ta:

Volume of solution = 2.50 L

Molarity = 0.48 M

Mass required = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity * volume in litter

Number of moles = 0.48 M * 2.50 L

Number of moles = 1.2 mol

Mass of HI:

Number of moles = mass/molar mass

Mass = Number of moles * molar mass

Mass = 1.2 mol * 127.9 g/mol

Mass = 153.48 g