You do an experiment in which you need 1.5 moles of tyrosine (C9H11 NO3). How

many grams must you weigh out?

65g

113 g

272 g

181 g

272 g

Explanation:

To know the amount of tyrosine that we must weigh, we must first calculate the relative molecular mass of tyrosine. This can be achieved by adding the individual molar Masses of the different elements present in the tyrosine.

Relative molecular mass of tyrosine (C9H11 NO3) = (12 x 9) + (11 x1) + 14 + (3x 16)

= 108 + 11 + 14 + 48

= 181

Next, we solve for the mass of tyrosine that will give 1.5moles of tyrosine. This can be done by:

Mass conc. = number of mole x relative molecular mass

Mass conc. = 1.5 x 181 = 271.5 = 272g

Therefore, to obtain 1.5 moles of tyrosine (C9H11 NO3), we must weigh 272g of tyrosine.