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29 February, 18:03

Calculate the milligrams of chlorine (35.453 g/mol) in a 3.44 g solution of 18.0 wt% CaCl2 (110.98 g/mol).

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  1. 29 February, 21:24
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    395 mg of Cl are in 3.44 g of CaCl₂

    Explanation:

    18.0 wt% CaCl₂ means that 18 g of salt, are contained in 100 g of solvent (assuming solvent as solution).

    Let's apply a rule of three:

    In 100 g of solution we have 18 g of salt

    In 3.44 g of solvent we have (3.44.18) / 100 = 0.1692 grams of salt.

    Now, let's convert this mass into moles (mass / molar mass)

    0.1692 mass / 110.98 g/m = 0.00558 moles

    1 mol of CaCl₂ has 1 mol of Ca and 2 moles of Cl

    Then, 0.00558 moles of CaCl₂, would have the double of moles of Cl

    0.00558 m. 2 = 0.01116 moles of Cl.

    Let's convert the moles into mass (mol. molar mass)

    0.01116 moles of Cl. 35.453g/m = 0.395 grams of Cl.

    Finally we convert grams to mg (x1000)

    0.395 g = 395 mg
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