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5 September, 13:57

If the take off velocity of an airplane on a runway is 300 km / hr with an acceleration of 1 m/s2. What is the take off time of the airplane?

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  1. 5 September, 15:38
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    83.33 seconds.

    Explanation:

    We are given;

    Take off velocity as 300 km/hr Acceleration as 1 m/s²

    We are required to calculate the take off time of the airplane.

    Step 1: Convert velocity from km/hr to m/s

    We are going to use the conversion factor.

    The conversion factor is 3.6 km/hr per m/s

    Therefore;

    Velocity = 300 km/hr : 3.6 km/hr per m/s

    = 83.33 m/s

    Step 2: Calculate the take off time

    We know that;

    v = u + at

    where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

    But, initial velocity is Zero

    Therefore;

    83.33 m/s = 1 m/s² * t

    Thus;

    time = 83.33 m/s : 1 m/s²

    = 83.33 seconds

    Therefore, the take off time is 83.33 seconds.
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