Aluminum bromide reacts with chlorine gas to produce aluminum chloride and liquid bromide,

according to the chemical equation below:

2AIBr + 3C1, 2AICI, + 3Br2

How many moles of Aluminum chloride are made if 779 g of chlorine gas are consumed?

7.5 mol of AlCl₃ will produce.

Explanation:

Given dа ta:

Mass of chlorine = 779 g

Moles of aluminium chloride = ?

Solution:

Chemical equation:

2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂

Number of moles of Cl₂:

Number of moles = mass / molar mass

Number of moles = 779 g / 71 g/mol

Number of moles = 11.3 mol

Now we will compare the moles of chlorine with AlCl₃.

Cl₂ : AlCl₃

3 : 2

11.3 : 2/3*11.3 = 7.5 mol