Ask Question
8 November, 20:58

Calculate the molar solubility of AgCl, using its Ksp value of 1.8 x 10-10.

+2
Answers (1)
  1. 8 November, 23:23
    0
    Answer:1.34 * 10^-5

    Explanation:

    AgCl = (Ag+) (Cl-)

    = (S) (S)

    = S²

    S stands for molar solubility

    Ksp = S² = 1.80 * 10^ - 10

    S = √[1.80 * 10^ - 10]

    =1.34 * 10^-5
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Calculate the molar solubility of AgCl, using its Ksp value of 1.8 x 10-10. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers