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1 August, 06:30

1 kg of Oxygen gas is present in a 500 L tank. Find the specific and molar volumes of the gas.

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  1. 1 August, 09:51
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    specific volume O2 = 0.5 Kg/m³

    molar volume O2 = 8 E-3 m³/mol

    Explanation:

    specific volume (Sv):

    ∴ Sv = 1 / ρ

    ∴ ρ = mass / volume

    ∴ V = 500 L * (m³/1000 L) = 0.5 m³

    ∴ ρ = 1 Kg / 0.5m³ = 2 Kg/m³

    ⇒ Sv = 1 / 2 Kg/m³ = 0.5 m³/Kg

    molar volume (Vm):

    ∴ Vm = volume/mol

    ∴ Mw O2 = 1000g O2 * (mol/16g O2) = 62.5 mol O2

    ⇒ Vm = 0.5 m³ / 62.5 mol

    ⇒ Vm = 8 E-3 m³/mol
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