An ideal gas with MW = 30 is flowing at a steady rate through a circular pipe (cross-section area of 57.8 cm^2) at a temperature of 1.60 * 10^2 °C and pressure of 49.3 psig. The volumetric flow rate is 940 L/min, what is the molar flow rate (mol/s) ?

Question

Chemistry

Bruno Hays

19 February, 16:05

An ideal gas with MW = 30 is flowing at a steady rate through a circular pipe (cross-section area of 57.8 cm^2) at a temperature of 1.60 * 10^2 °C and pressure of 49.3 psig. The volumetric flow rate is 940 L/min, what is the molar flow rate (mol/s) ?

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Answers (1)

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Devan Mooney · Answer 1

n = 1.48 mol/s

Explanation:

ideal gas:

PV = RTn

⇒ n = PV/RT

∴ T = 1.60 E2 °C = 160°C = 433 K

∴ R = 0.082 atm. L/K. mol

∴ P = 49.3 psig * (atm / 14.6959psig) = 3.35 atm

∴ V = 940 L/min

⇒ n = ((3.35) * (940)) / ((0.082) * (433))

⇒ n = 88.813 mol/min * (min / 60s)

⇒ n = 1.48 mol/s