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ChemistryChemistry
18 March, 02:11

The following reaction shows sodium hydroxide reacting with sulfuric acid.

4NaOH + 2H2SO4 → 2Na2SO4 + 4H2O

How many grams of Na2SO4 are produced from 10.0 grams of NaOH?

(Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.065 g/mol)

17.8 grams

19.2 grams

35.5 grams

38.5 grams

+1
Answers (1)
  1. 18 March, 03:03
    0
    Answer: 17.8grams

    Explanation:

    Equate the number of moles of NaOH to the number of moles of Na2SO4

    No of mole = reacting mass / molar mass

    10/40 x 4 = mass of Na2SO4/142 x 2

    10/160 = x/284

    X = 284 x 10/160

    X = 17.8 grams
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Home » Chemistry » The following reaction shows sodium hydroxide reacting with sulfuric acid. 4NaOH + 2H2SO4 → 2Na2SO4 + 4H2O How many grams of Na2SO4 are produced from 10.0 grams of NaOH? (Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.
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