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14 January, 21:00

a 0.5678 of KHP required 26.64cm³ of NaOH to complete neutralization. calculate the molarity of the NaOH solution

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  1. I
    14 January, 23:05
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    0.5678 G X GRAMS

    KHC8H4O4 + NaOH = NaKC8H4O4 + H2O

    1 MOL 1 MOL

    0.5678G X 204G/MOL = 0.00278 MOL KHC8H4O4

    0.00278 MOL KHC8H4O4 X 1 MOLE NaOH/1 MOLE KHC8H4O4=0.00278 MOL NaOH

    0.00278 MOL NaOH/26.26ml=0.106 molar
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