The xenon gas inside a car headlight bulb has a pressure of 2.00 atm at a temperature of 300 K. If the temperature of the gas rises to 1200 K when the headlights are switched on, what will be the new pressure in the bulb

P₂ = 8 atm

Explanation:

According to the Gay Lussac's law,

The pressure of given amount of gas is directly proportional to the its kelvin temperature at constant volume.

P ∝ T

P = K T

P/T = K

P₁/T₁ = P₂/T₂

Given dа ta:

Initial pressure = 2.00 atm

Initial temperature = 300 K

Final temperature = 1200 K

Final pressure = ?

Solution:

Formula:

P₁/T₁ = P₂/T₂

P₂ = P₁*T₂/T₁

P₂ = 2.0 atm * 1200 K / 300 K

P₂ = 2400 atm / 300

P₂ = 8 atm