The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58 cal of heat.

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m * c * ΔT

Given dа ta:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper = 0.093 cal/g.°C

temperature change = ΔT=?

Solution:

Q = m * c * ΔT

58 cal = 28 g * 0.093 cal / g.°C * ΔT

58 cal = 2.604 cal.°C * ΔT

58 cal / 2.604 cal.°C = ΔT

22.27 °C = ΔT