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28 June, 03:49

What is the molarity of ZnCl2 that forms when 20.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 255 mL. Zn (s) + CuCl2 (aq) →ZnCl2 (aq) + Cu (s)

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  1. 28 June, 04:58
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    Molarity ZnCl2 = 1.2 M

    Explanation:

    Step 1: Data given

    Mass of zinc = 20.0 grams

    Atomic mass of zinc = 65.38 g/mol

    Volume = 255 mL = 0.255 L

    Step 2: The balanced equation

    Zn (s) + CuCl2 (aq) → ZnCl2 (aq) + Cu (s)

    Step 3: Calculate moles Zn

    Moles Zn = mass Zn / molar mass Zn

    Moles Zn = 20.0 grams / 65.38 g/mol

    Moles Zn = 0.306 moles

    Step 4: Calculate moles ZnCl2

    For 1 mol Zn we need 1 mol CuCl2 to produce 1 mol ZnCl2 and 1 mol Cu

    For 0.306 moles Zn we have 0.306 moles ZnCl2

    Step 5: Calculate molarity ZnCl2

    Molarity = 0.306 moles / 0.255 L

    Molarity ZnCl2 = 1.2 M
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