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6 January, 20:13

Part A How many moles of NH3 can be produced from 13.5 mol of H2 and excess N2? Express your answer numerically in moles. View Available Hint (s) nothing mol NH3

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  1. 7 January, 00:08
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    9moles of NH3

    Explanation:

    First, we need to write a balanced equation for the reaction. This is illustrated below:

    N2 + 3H2 - > 2NH3

    From the equation,

    3 moles of H2 produced 2moles of NH3.

    Therefore, 13.5 mol of H2 will produce = (13.5 x 2) / 3 = 9moles of NH3
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