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27 March, 00:18

Calculate the amount of energy that is absorbed by 75 g ... water

from 22.5 °C to 37.8 °C. The specific heat of water is 1 cal / g x °C

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  1. 27 March, 04:27
    0
    Q = 1147.5 cal

    Explanation:

    Given dа ta:

    Energy absorbed = ?

    Mass of water = 75 g

    Initial temperature = 22.5°C

    Final temperature = 37.8°C

    Specific heat of water = 1 cal/g.°C

    Solution:

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = T2 - T1

    ΔT = 37.8°C - 22.5°C

    ΔT = 15.3 °C

    Q = m. c. ΔT

    Q = 75 g. 1 cal/g.°C. 15.3 °C

    Q = 1147.5 cal
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