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16 April, 19:36

5.

A 120.0 g sample of Thallium-208 decays. How much of the sample will remain after 3 half lifest

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  1. 16 April, 22:10
    0
    15.0 g

    Explanation:

    We are given;

    Original sample of Thallium-208 as 120.0 g The number of half lives as 3

    We are required to calculate the remaining mass after three half lives

    We are going to use the formula;

    N = N₀ * 0.5^n

    where, N is the remaining mass, N₀ is the original mass and n is the number of half lives.

    Therefore;

    N = 120.0 g * 0.5^3

    = 15.0 g

    Thus, the remaining mass of Thallium-208 is 15.0 g

    Alternatively;

    Since after every half life the mass reduces by half of the original then we can half a chain showing the reduction after three half lives;

    120.0 g → 60.0 g (120 * 0.5) → 30.0 g (60 * 0.5) → 15.0 g (30 * 0.5)

    Therefore, the remaining mass after three half lives is 15.0 g
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