What volume of 0.100M of sodium trioxonitrate (v) contains 5g of a solute? (Na=23, N=14, O=16)

0.79L

Explanation:

From the question given, the following were obtained:

Molarity = 0.1M

Molar Mass of HNO3 = 1 + 14 + (16x3) = 1 + 14 + 48 = 63g/mol

Mass of HNO3 = 5g

Number of mole = ?

Number of mole = Mass / Molar Mass

Number of mole of HNO3 = 5/63 = 0.079mole

Now we can obtain the volume of the solution as follows:

Molarity = 0.1M

Mole = 0.079mole

Volume = ?

Molarity = mole/Volume

Volume = mole / Molarity

Volume = 0.079/0.1

Volume = 0.79L