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26 May, 18:54

Calculate the molality of a solution formed by adding 26.0 g NaCl to 74.0 g of water at 10.0 °C. The density of this solution is 1.203 g/mL at 10.0 °C. The molar mass of NaCl = 58.44 g/mol and the molar mass of H2O = 18.02 g/mol.

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  1. 26 May, 20:18
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    Molality for the solution is 6.01 m/kg

    Explanation:

    Molality means moles of solute in 1kg of solvent.

    The solute is NaCl.

    The solvent is H₂O.

    Let's prepare the rule of three

    In 74 g of solvent, there are 26 g of NaCl

    In 1000 g of solvent, there are (1000.26) / 74 = 351.35 g

    Let's convert this mass in moles.

    Mass / Molar mass = moles

    351.35 g / 58.44 g/m = 6.01 moles
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